First of all let's calculate the centroid location.
It is not too hard to calculate directly with integral, but the Guldin-Pappus relation gives this instantly.
Rotate the half disc through its diameter, the generated volume (a full sphere) is V = 4/3 π R³
Area of half disc is S = πR²/2 and the Guldin relation gives : 2πOG × S = V
That is 2πOG × πR²/2 = 4/3 πR³, and after reducing :
OG = 4/(3π) R
Let's try now to split the half disc in two equal area parts through a segment MN.
Of course cutting in two quarter discs goes through G (by symmetry), but in other cases, there is no reason for MN to go through G, and it is generally not the case. We can be then interested in finding the envelope of MN.
We have two cases to consider :
ON/R = - t/cos(t)
This allows to construct (calculate) point N for every location of M, and find the envelope.
The limit position of M is when |ON| = R, resulting into t0 = ±0.7390851332151607... that is 42.35°
Equation t = cos(t) gives this value with a 10-15 accuracy in just a few iterates of Newton method :
We could also depress repeatedly the "cos" key of any pocket calculator in radian mode, but this requires much more iterates !
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We get then the three cuts MN which go through G :
The trivial case Oy from case 2 (touching point with envelope in A)
Two other cases (from case 1) :
We get then cos(TOG) = OT/OG = R sin(π/4 - t0/2) / (4R/(3π)) = 3 π sin(π/4 - t0/2) / 4
Line MN going through G has an angle of φ = 17.854464...° with diameter xx'
Detailed calculations of envelope let as exercise.
Prove that T is midpoint of MN.Solution